When starting a foot race, a 70.0kg sprinter exerts an average force of 650 N backward on the ground for 0.800 s. How far does he travel? a)1.48 m (b) 2.97m (c) 5.95 m (d) 11.9m

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Answer:

Answer is option b) 2.97m

Explanation:

With the relationship between the force exerted by the runner and the mass that it has, I can determine the acceleration it will have:

F= m × a ⇒ a= (650 kg ×(m/s^2)) / (70kg)= 9.286 (m/s^2)

With the acceleration that prints the force exerted and the time I can determine the distance traveled in the interval:

Distance= (1/2) × a × t^2 = (1/2) × 9.286 (m/s^2) × ((0.8s)^2)= 2.97m

The distance covered by the runner is 2.96 m. Option B is the correct answer.

How do you calculate the distance?

Given that the mass m of the runner is 70.0 kg and the average force exerted is 650 N backward on the ground for 0.800 s.

The force can be defined as below.

[tex]F = ma[/tex]

Where a is the acceleration and F is the force exerted. The acceleration can be calculated by substituting the values in the above formula.

[tex]a = \dfrac {F}{m}[/tex]

[tex]a = \dfrac { 650}{70}[/tex]

[tex]a = 9.28 \;\rm m/s[/tex]

The distance traveled by the runner can be calculated by the equation given below.

[tex]s = ut + \dfrac {1}{2}at^2[/tex]

Where s is the distance covered and u is the initial velocity. Let us consider that the initial velocity of the runner is zero, then the distance will be,

[tex]s = \dfrac {1}{2}at^2[/tex]

[tex]s = \dfrac {1}{2}\times 9.28\times (0.800)^2[/tex]

[tex]s = 2.96\;\rm m[/tex]

Hence we can conclude that the distance covered by the runner is 2.96 m. Option B is the correct answer.

To know more about the distance and acceleration, follow the link given below.

https://brainly.com/question/14363745.