Answer:
[tex]b=m/[3R+L][/tex]
Step-by-step explanation:
we have
[tex]3Rb= -Lb+m[/tex]
Solve for b
That means -----> Isolate the variable b
Adds Lb both sides
[tex]3Rb+Lb= -Lb+m+Lb[/tex]
[tex]3Rb+Lb=m[/tex]
Factor b left side
[tex]b[3R+L]=m[/tex]
Divide by [3R+L] both sides
[tex]b[3R+L]/[3R+L]=m/[3R+L][/tex]
Simplify the left side
[tex]b=m/[3R+L][/tex]
Answer:
b = [tex]\frac{m}{(3R + L)}[/tex]
Step-by-step explanation:
Solving for B in the following equation simply means to make B subject of the formula.
3Rb= −Lb+m
The first step is to add Lb to both-side of the equation, we want to cancel-out Lb from the right-hand side of the equation, so as to group all the variable containing b at the left-hand side of the equation.
3Rb + Lb = -Lb + Lb + m
On the right-hand side of the equation -Lb will cancel-out +Lb, leaving us with just m
3Rb + Lb = m
Next is to factor out b on the right-hand side of the equation
b( 3R + L) = m
Next is to divide both-side of the equation by (3R + L)
[tex]\frac{b(3R+L)}{(3R+ L)}[/tex] = [tex]\frac{m}{(3R + L)}[/tex]
On the left-hand side of the equation, ( 3R + L ) on the numerator will cancel- out (3R+L) on the denominator leaving us with just b
b = [tex]\frac{m}{(3R + L)}[/tex]
