Grains of fine California beach sand are approximately spheres with an average radius of 50 μm and are made of silicon dioxide, which has a density of 2.7 × 103 kg/m3. What mass of sand grains would have a total surface area (the total area of all the individual spheres) equal to the surface area of a cube 0.8 m on an edge?

Respuesta :

Answer:

The mass of sand grains is [tex]1.413\times10^{-9}\ kg[/tex]

Explanation:

Given that,

Radius [tex]r = 50\ mu m[/tex]

Density[tex]\rho=2.7\times10^{3}\ kg/m^3[/tex]

Cube edge = 0.8 m

We need to calculate the mass of sand grains

Using formula of density

[tex]\rho = \dfrac{m}{V}[/tex]

[tex]m=\rho\times V[/tex]

Where, [tex]\rho[/tex] = density

V = volume

Put the value into the formula

[tex]m =2.7\times10^{3}\times\dfrac{4}{3}\pi\timesr^3[/tex]

[tex]m=2.7\times10^{3}\times\dfrac{4}{3}\times3.14\times(50\times10^{-6})^3[/tex]

[tex]m=1.413\times10^{-9}\ kg[/tex]

Hence, The mass of sand grains is [tex]1.413\times10^{-9}\ kg[/tex]