Respuesta :
Answer:
Part A. At least 6 hours
Part B. In less than 2.5 hours Elijah will be behind Mercedes
Part C. In more than 2.5 hours Elijah will be ahead Aubrey
Step-by-step explanation:
D = distance
v =speed
t = time
Formula connecting D, v and t:
[tex]D=v\cdot t[/tex]
Part A.
Steve's speed: [tex]v=3.5\ mph[/tex]
Distance: at least 21 miles
Time: unknown, so
[tex]3.5\cdot t\ge 21\\ \\35t\ge 210\ [\text{Multiplied by 10}]\\ \\t\ge \dfrac{210}{35}\\ \\t\ge \dfrac{30}{5}\\ \\t\ge 6[/tex]
It would take Steve at least 6 hours to walk at least 21 mi on Day 1.
Part B.
Mercedes's speed: [tex]v_M=2.4\ mph[/tex]
Elijan's speed: [tex]v_E=3.2\ mph[/tex]
Elijan's Distance walked: [tex]D_E[/tex] miles
Mercedes's Distance walked: [tex]D_M[/tex] miles
Time: x hours
Mercedes is 2 miles ahead, so
[tex]D_E=3.2x\\ \\D_M=2.4x+2[/tex]
Elijan will be behind when
[tex]D_E<D_M\\ \\3.2x< 2.4x+2\\ \\3.2x-2.4x<2\\ \\0.8x<2\\ \\8x<20\ [\text{Multiplied by 10}]\\ \\x<\dfrac{20}{8}\\ \\x<2.5\ hours[/tex]
In 2.5 hours Elijan will catch up Mercedes, and in less than 2.5 hours Elijah will be behind Mercedes.
Part C.
Aubrey's speed: [tex]v_M=3\ mph[/tex]
Elijan's speed: [tex]v_E=3.2\ mph[/tex]
Elijan's Distance walked: [tex]D_E[/tex] miles
Aubrey's Distance walked: [tex]D_A[/tex] miles
Time: x hours
At the beginning of Day 3, Elijah starts walking at the marker for Mile 42, and Aubrey starts walking at the marker for Mile 42.5.
[tex]D_E=42+3.2x\\ \\D_A=42.5+3x[/tex]
Elijan will be ahead of Aubrey when
[tex]D_E>D_A\\ \\42+3.2x> 42.5+3x\\ \\3.2x-3x>42.5-42\\ \\0.2x>0.5\\ \\2x>5\ [\text{Multiplied by 10}]\\ \\x>\dfrac{5}{2}\\ \\x>2.5\ hours[/tex]
In 2.5 hours Elijan will catch up Aubrey, and in more than 2.5 hours Elijah will be ahead Aubrey.