Answer:
0.766 m
Explanation:
initial velocity of puck, u = 6 m/s
final velocity of puck, v = 40 m/s
time taken by the puck, t = 3.33 x 10^-2 s
Let the acceleration of puck is a and the distance traveled by the puck is s in the given time.
Use first equation of motion
[tex]v=u+at[/tex]
[tex]40=6+a \times 3.33\times 10^{-2}[/tex]
a = 1021.02 m/s^2
Now to find the distance, use third equation of motion
[tex]v^2=u^2+ 2\times a \times s[/tex]
[tex]40^2=6^2+ 2\times 1021.02 \times s[/tex]
s = 0.766 m
Thus, the distance traveled by the puck is 0.766 m.
