Answer:
She must invest $[tex]N_0=\frac{N_3}{(1+0.025)^3}= \frac{6000}{1.076}=5571.60[/tex]
Step-by-step explanation:
Using the formula fot compund interest:
[tex]N_n=N_0*(1+0.025)^n[/tex]
Replacing n=3,[tex]N_3=6000[/tex] and solving for [tex]N_{0}[/tex]: