Answer:
The magnitude of his average velocity for the 200.0 m is zero.
Explanation:
Given that,
Distance = 100.0 m
Time = 9.86 s
Now, back to his starting point
Time = 90.9 s
Average velocity :
Average velocity is equal to the total displacement divided by the total time.
In mathematical form,
[tex]v_{avg}=\dfrac{D}{T}[/tex]
Where, D = Displacement
t = time
He started at the Start line, and ended at the Start Line.. his Net displacement will be Zero so the average velocity will be
Using formula of average velocity,
[tex]v_{avg}=\dfrac{100-100}{90.9-9.86}[/tex]
[tex]v_{avg}=0[/tex]
Hence, The magnitude of his average velocity for the 200.0 m is zero.