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Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m . Simultaneously, each puck is given a quick push, and they begin to slide directly toward each other. Puck A moves with a speed of 3.10 m/s , and puck B moves with a speed of 3.50 m/s . What is the distance covered by puck A by the time the two pucks collide?

Respuesta :

Answer:8.45 m

Explanation:

Given

Two pucks are separated by a distance of 18 m

Puck A is given a push such that its velocity is 3.10 m/s

Puck B velocity is 3.50 m/s

Let they meet after time t such that Puck has traveled x m and Puck B 18-x

For same time

[tex]\frac{x}{3.10}=\frac{18-x}{3.50}[/tex]

[tex]6.6x=18\times 3.1[/tex]

x=8.45 m

18-x=9.55 m

So Puck has traveled a distance of 8.45 m

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