A car is traveling down the highway at speed v when the driver slams on the brakes and skids to a stop in a distance d. Assuming the same frictional force, how far would the car slide if its speed was 2v?

Respuesta :

Answer:

It would slide a distance 4d

Explanation:

From the first scenario where the speed is v and the distance sliding is d we can calculate de value of the acceleration:

[tex]V_{f}^{2} =V_{o}^{2} - 2.a.x[/tex]

We know that

[tex]V_{f}=0[/tex]

[tex]V_{o}=v[/tex]

[tex]x=d[/tex]

So, the acceleration is [tex]a=\frac{v^{2}}{2d}[/tex]

Now, using the same formula and with the new value for [tex]V_{o}=2v[/tex] we can solve for x from:

[tex]0=(2v)^{2} -2.\frac{v^{2}}{2d} .x[/tex]

x=4d