Answer: The correct answer is Option c.
Explanation:
For concave mirror, sign convention used is:
f = +ve
u = +ve (object is in front of mirror)
[tex]\frac{1}{u}+\frac{1}{v}=\frac{1}{f}[/tex]
where,
u = distance of object from mirror = +3 cm
v = distance of image from mirror = ?
f = focal length of the mirror = +1 cm
Putting values in above equation, we get:
[tex]\frac{1}{(+3)}+\frac{1}{v}=\frac{1}{1}\\\\v=\frac{2}{3}cm[/tex]
As, the image distance is coming out to be positive, this means that image is real.
[tex]m=-\frac{v}{u}[/tex]
We are given:
[tex]u=3cm\\v=\frac{2}{3}cm[/tex]
Putting values in above equation, we get:
[tex]m=-\frac{\frac{2}{3}}{3}\\\\m=\frac{-1}{2}[/tex]
As, the magnification is coming out to be negative, this means that image is inverted with respect to object. Also, the image is reduced in size.
Hence, the correct answer is Option c.