A tennis ball is thrown straight up into the air with an initial velocity of 6.8 m/s. How long does it take to reach the top of the trajectory?

Respuesta :

Answer:

0.69 s

Explanation:

The tennis ball moves upward with constant acceleration of

g = 9.8 m/s^2

in the downward direction. Therefore, the velocity of the ball at time t is given by

v(t) = u - gt

where

u = 6.8 m/s is the initial velocity

g is the acceleration of gravity

t is the time

At the top of the trajectory, the ball has velocity

v = 0

Solving the formula for t, we find the time taken for the ball to reach the top:

[tex]t=\frac{v-u}{-g}=\frac{0-6.8}{-9.8}=0.69 s[/tex]