Answer:
The average rate of change in the interval [0,3] is 1
Step-by-step explanation:
we know that
To find the average rate of change, we divide the change in the output value by the change in the input value
[tex]\frac{g(t2)-g(t1)}{t2-t1}[/tex]
In this problem we have
The interval [t1,t2] is [0,3]
so
[tex]t1=0[/tex]
[tex]t2=3[/tex]
[tex]g(t1)=g(0)=1[/tex]
[tex]g(t2)=g(3)=4[/tex]
Substitute
[tex]\frac{4-1}{3-0}=1[/tex]
therefore
The average rate of change in the interval [0,3] is 1
