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  • 09-09-2019
  • Mathematics
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Find the nth term of 14,23,32,41

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Cxlver
Cxlver Cxlver
  • 09-09-2019

[tex]\\$Let a_n$ be the following sequence: 14, 23, 32, 41, ...\\a_1 = 14 \ \ \ a_2 = 23 \ \ \ a_3 = 32 \ \ \ a_4 = 41\\$Observe that $ a_2 - a_1 = a_3 - a_2 = a_4 - a_3 = 9 =>$ a_n - $Arithmetic progression$=> a_n = 14 + 9(n-1)[/tex]

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