Explanation:
It is given that,
Mass of the aircraft 1, m₁ = 1400 kg
Mass of aircraft 2, m₂ = 1500 kg
Initially, the aircraft 2 is at rest, u₂ = 0
Initial speed of the aircraft 1, u₁ = 40 m/s
After the collision, the total speed of the system, V = 19.3 m/s
Time, t = 8.2 s
Since, two objects stick together it is a case of inelastic collision. The acceleration of the system is given by :
[tex]a=\dfrac{V}{t}[/tex]
[tex]a=\dfrac{19.3\ m/s}{8.2\ s}[/tex]
[tex]a=2.35\ m/s^2[/tex]
Distance covered by the system before stopping is given by :
[tex]x=\dfrac{1}{2}\times a\times t^2[/tex]
[tex]x=\dfrac{1}{2}\times 2.35\times (8.2)^2[/tex]
x = 79.007 meters
Hence, this is the required solution.
