danyal0112
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I give a ball a push on an acclivity. The "start velocity" is on 7m/s. The time it took the ball to get back to me was 10 seconds. The acceleration is a constant. How much is the acceleration?

Respuesta :

Answer:

7÷10

Explanation:

initial velocity=7m/s

final velocity=0m/s

MathPhys

Answer:

-1.4 m/s²

Explanation:

The initial velocity is 7 m/s.  When the ball rolls back, its velocity is -7 m/s.

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (-7 m/s − 7 m/s) / 10 s

a = -1.4 m/s²

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