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An iron ore was found to contain 92.0% pyrite (fool's gold). Pyrite has the formula FeS2and is 46.5% iron. How many grams of iron are there in 52.5 grams of iron ore? Give only numerical value in the box below (no units)

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Answer:

There are 22.46 g of iron in 52.5 g of iron ore.

Explanation:

Iron ore:

92.0 FeS₂  _______  100 g iron ore

      x          _______  52.5 g iron ore

               x = 48.3 g FeS₂

Pyrite:

100 g FeS₂  ________ 46.5 g Fe

48.3 g FeS₂ ________     y

              y = 22.46 g Fe

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