Respuesta :
Answer:
The mass of urea produced is 2.175kg/min
Explanation:
Step 1: The balanced equation
2 NH3(g) + CO2(g) → H2NCONH2(s) + H2O(g)
Step 2: Given data
Ammonia gas (NH3) at 223°C (= and 90 atm flows into a reactor at a rate of 580 L/min
Carbon dioxide( CO2) at 223°C and 48 atm flows into the reactor at a rate of 600. L/min.
Step 3: Calculate
⇒NH3:
(P1*V1)/ T1 = (P2*V2)/T2
P1 = 90 atm
V1 = 670L
T1 = 496 K
P2 = 1 atm
V2 = TO BE DETERMINED
T2= 273K
P1V1T2 = P2V2T1
90atm*670L*273K = 1atm*V2*496K
V2 = (90 x 670 x 273)/496
V2 = 33189 L ( Volume at STP)
At STP 1 mole = 22.4 L
This means 33,189/22.4 = 1,482 moles
This gives us a rate of 1482g /min NH3
CO2:
P1 = 47 atm
V1 = 600L
T1 = 496 K
P2 = 1 atm
V2 = TO BE DETERMINED
T2= 273K
47atm*600L*273K = 1atm*V2*496K
V2 = (47*600*273) /496
V2 = 15,521L
15,521 ÷ 22.4 = 692.92 moles = 692.92g/min
1482g /min NH3 + 692.92g/min = 2.175kg/min
Answer:
38,456.4 grams of urea is produced per minute by this reaction.
Explanation:
[tex]2 NH_3(g) + CO_2(g)\rightarrow H_2NCONH_2(s) + H_2O(g)[/tex]
Ammonia gas at 223°C and 90 atm flows into a reactor at a rate of 580 L/min.
Volume of ammonia = V = 580 L/min
Temperature of the gas = T = 223°C = 496 K
Pressure of the ammonia gas = P = 90 atm
Moles of ammonia per minute = n
[tex]PV=nRT[/tex]
[tex]n=\frac{90 atm\times 580 L/min}{0.0821 atm L/mol K\times 496 K}[/tex]
[tex]n=1,281.87 mol/min[/tex]
Carbon dioxide at 223°C and 48 atm flows into the reactor at a rate of 600 L/min.
Volume of gas= V = 600 L/min
Temperature of the gas = T = 223°C = 496 K
Pressure of the ammonia gas = P = 48 atm
Moles of ammonia per minute = n
[tex]PV=nRT[/tex]
[tex]n=\frac{48 atm\times 600 L/min}{0.0821 atm L/mol K\times 496 K}[/tex]
[tex]n=707.24 mol/min[/tex]
Moles of ammonia gas per minute = 1,281.87 mol
Moles of carbon dioxide per minute = 707.24 mol
According to reaction 2 mol of ammonia gas reacts with 1 mol of carbon dioxide.
Then 1,281.87 moles of ammonia will react with:
[tex]\frac{1}{2}\times 1,281.87 mol=640.94 mol[/tex] of carbon dioxide.
Carbon dioxide is in excess amount. Amount of urea will depend upon amount of ammonia.
According to reaction 2 mol of ammonia gas gives 1 mol of urea.
Then 1,281.87 moles of ammonia will give:
[tex]\frac{1}{2}\times 1,281.87 mol=640.94 mol[/tex] of urea.
Mass of 640.94 moles of urea : 640.94 mol × 60 g/mol=38,456.4 g
38,456.4 grams of urea is produced per minute by this reaction.
