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A careless university student leaves her iClicker device behind with probability 1/4 each time she attends a class. She sets out with her iClicker device to attend 5 different classes (each class is in a different lecture theatre). Part 1) If she arrives home without her iClicker device (after attending 5 classes), what is the probability (to 3 SIGNIFICANT figures) that she left it in the 5th class?

Respuesta :

Answer:

0.0791

Step-by-step explanation:

student forgets iClicker device with probability 1/4 each time she attends a class.

She sets out with her iClicker device to attend 5 different classes

A - forget device

A' - do not forget device

P(A) = 1/4

P(A') = 3/4

If she arrives home without her iClicker device (after attending 5 classes), what is the probability (to 3 SIGNIFICANT figures) that she left it in the 5th class?

So, she will not forget in 1st class AND not forget in 2nd class AND not forget in 3rd class AND not forget in 4th class AND will forget in 5th class, so:

1st     2nd     3rd     4th     5th

3/4      3/4     3/4     3/4      1/4    =  0.0791

lhmarianateixeira

In this exercise we have to use the knowledge of probability to calculate the chances of an event to occur so we have to:

0.0791

Thus, through the information given in the exercise statement we find that:

  • student forgets iClicker device with probability 1/4 each time she attends a class.
  • She sets out with her iClicker device to attend 5 different classes
  • A - forget device and P(A) = 1/4
  • A' - do not forget device and P(A') = 3/4

So the probability that the event occurs is:

[tex]3/4 + 3/4 + 3/4 + 3/4 + 1/4 = 0.0791[/tex]

See more about probability at brainly.com/question/862972

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