What is the sum of the coefficients when the following equation is balanced using the lowest whole-numbered coefficients?
_____ PH3(g) + _____ O2(g) → _____ P4O10(s) + _____ H2O(g)

(A) 22
(B) 12
(C) 10
(D) 19

Respuesta :

Answer: Option (D) is the correct answer.

Explanation:

A chemical equation in which the number of atoms on the reactant side are equal to the number of atoms on product side then it is known as a balanced equation.

For example, [tex]PH_{3}(g) + O_{2}(g) \rightarrow P_{4}O_{10}(s) + H_{2}O(g)[/tex]

This equation is not balanced yet as the number of atoms on reactant side are different from the atoms on product side.

Hence, we will balance this equation as follows.

      [tex]4PH_{3}(g) + 8O_{2}(g) \rightarrow P_{4}O_{10}(s) + 6H_{2}O(g)[/tex]

Therefore, sum of the coefficients will be as follows.

            Sum = 4 + 8 + 1 + 6

                     = 19

Thus, we can conclude that the sum of the coefficients when the given equation is balanced using the lowest whole-numbered coefficients is 19.