Explanation:
It is given that,
Total charge carried in a bolt, q = 31 C
Time taken, [tex]t=2.4\ ms=2.4\times 10^{-3}\ s[/tex]
Let I is the magnitude of current flowing in a bolt. The total charge flowing per unit time is called electric current. Mathematically, it is given by :
[tex]I=\dfrac{q}{t}[/tex]
[tex]I=\dfrac{31\ C}{2.4\times 10^{-3}\ s}[/tex]
I = 12916.66 A
Let n is the number of electrons. According to the quantization of charges,
q = ne
[tex]n=\dfrac{q}{e}[/tex]
e is the charge on electron
[tex]n=\dfrac{31}{1.6\times 10^{-19}}[/tex]
[tex]n=1.93\times 10^{20}[/tex]
Hence, this is the required solution.
