Answer:
5 milliliter of sterile water will be added to a 1 gram vial.
Explanation:
Concentration of dosage required = 200 mg/ml
That is 200 mg of Cefazolin in 1 mL of solution.
1 mg = 0.01 g
1 mL = 0.001 L
[tex]200 mg/ml=\frac{200\times 0.001 g}{0.001 L}=200 g/L[/tex]
The for 1 grams of Cefazolin will be present in x liters of water.
[tex]\frac{1 g}{x}=200 g/L[/tex]
[tex]x=\frac{1 g}{200 g/L}=0.005 L = 5 ml[/tex]
5 milliliter of sterile water will be added to a 1 gram vial.