An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge denisity σ1 = 0.37 μC/m2. Another infinite sheet of charge with uniform charge density σ2 = -0.19 μC/m2 is located at x = c = 28 cm.. An uncharged infinite conducting slab is placed halfway in between these sheets ( i.e., between x = 12 cm and x = 16 cm). What is Ex(P), the x-component of the electric field at point P, located at (x,y) = (6 cm, 0)?

Respuesta :

Answer:

The x-component of the electric field at point P --  31,638.41

Explanation:

Given data:

charge density [tex]\sigma_1 =0.37 \muC/m^2[/tex]

Another charge density [tex]\sigma_2 = -0.19 \mu C/m^2[/tex]

Electric field due to infinite sheet of charge is given as E

[tex]E = \frac{\sigma}{2\epsilon}[/tex]

[tex]E_{NET} = E_1 + E_2[/tex]

             [tex]= \frac{\sigma_1}{2\epsilon} + \frac{\sigma_2}{2\epsilon}[/tex]

            [tex]=  \frac{0.37\times 10^{-6}}{2\times 8.85\times 10^{-12}} + \frac{0.19\times 10^{-6}}{2\times 8.85\times 10^{-12}}[/tex]

             = 31,638.41