Answer : The correct option is, (a) [tex]2Na^+[/tex]
Explanation :
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced molecular equation will be,
[tex]Na_2SO_4(aq)+Ca(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+CaSO_4(s)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2Na^+(aq)+SO_4^{2-}(aq)+Ca^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO^{3-}(aq)+CaSO_4(s)[/tex]
In this equation the species present are, [tex]2Na^+,2NO_3^-,Ca^{2+}\text{ and }SO_4^{2-}[/tex] are the spectator ions.
Hence, the complete ionic equation contains specie is [tex]2Na^+[/tex]