Answer:
160.75 N
Explanation:
The downward velocity has no effect on the force situation, it is only changes in velocity (plus, of course, gravity, which is always there) that require a force. At constant velocity, the bottom spring s_3 is supporting its mass m_3 to balance gravity.
As the elevator slows, though, it also ends up slowing down the spring arrangement, too. However, because the stretching takes time, it means that some damped harmonic motion will be set up in the spring chain.
When the motion has finally damped out, the net force the bottom spring s3 exerts on m3 has two components--that of gravity and of the deceleration of the elevator:
F_3net = m3 * (g + a) = 10.5×(9.81+5.5)= 10.5×15.31= 160.75 N
Force is defined by the product of mass and acceleration. It is denoted by [tex]\frac{m}{s^{2} }[/tex] . The force exerted by the bottom spring on the bottom mass will be 160.75 [tex]\frac{m}{s^{2} }[/tex] .
Force is defined by the product of mass and acceleration. It is denoted by [tex]\frac{m}{s^{2} }[/tex] . It has the ability to stop or change the motion of the body.
it can also change the shape and size of an object on which the force is applied.
When the elevator is moving downwards the elevator work in the favour of gravity. As the elevator is moving downwards the dlmbert force is also acting in the direction of motion.
Dlmbert force is acting in the direction of motion. which is given by the product of mass and acceleration acted in that direction.
Given
acceleration (a) = 5.5 m/s2
F = Mg + Ma
F = M (g +a )
F = 10.5( 9.81 + 5.5 )
F = 160.75 [tex]\frac{m}{s^{2} }[/tex].
Hence the force exerted by the bottom spring on the bottom mass will be 160.75 [tex]\frac{m}{s^{2} }[/tex] .
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https://brainly.com/question/26115859
