Answer:
The numbers are 46 and 32
Solution:
Let us assume the numbers are x and y.
One number is 14 less than another,
so [tex]x-14=y[/tex] …………. (i)
If their sum is increased by 7, the result is 85
So,[tex]x+y+7=85[/tex]
[tex]\Rightarrow x+y=78[/tex]
[tex]\Rightarrow x+x-14=78[/tex] (//substituting value from (i))
[tex]\Rightarrow 2 x=92[/tex]
[tex]\Rightarrow x=46[/tex]
So, [tex]y=(46-14)=32[/tex]
The numbers are 46 and 32.
