Respuesta :

amhugueth

Answer:

[tex]a=0.22m/s^2[/tex]

Explanation:

To find the acceleration we need to solve the following formula:

[tex]a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}[/tex]

Since the time interval is 1.33 min

[tex]t_{2}-t_{1}=1.33min*\frac{60s}{1min}=80s[/tex]

[tex]a=\frac{(37.5-19.4)m/s}{80s}=0.22m/s^2[/tex]

david8644

Answer:

Acc= 0,22m/s^2

Explanation:

Remember that acceleration is the change in velocity over a certain period of time, in most of the cases is measured in m/s*2, to calculate acceleration you need to use the next formula:

[tex]Acc=\frac{Vf-Vo}{t} \\[/tex]

Now we convert 1,33 mins to seconds:

1,33*60=79,8s

So if you have this formula we just insert the values into the formula:

[tex]Acc=\frac{37,5m/s-19,4m/s}{79,8s} \\Acc=\frac{18,1}{79,8s}\\Acc=0,22m/s^2[/tex]

So the acceleration of the car would be 0,22m/s^2

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