Answer:
141.147 km
Explanation:
[tex]sin45=\frac{BD}{BC}\\\Rightarrow BD=BCsin45\\\Rightarrow BD=40\times sin45\\\Rightarrow BD=28.28\ km[/tex]
Now, AE=BD also CD=BD as the angle B and C are equal
So, from Pythagoras theorem
AC² = AE²+(CD+DE)²
[tex]AC=\sqrt{AE^2+(CD+DE)^2}\\\Rightarrow AC=\sqrt{(40\times sin45)^2+(110+40\times sin45)^2}\\\Rightarrow AC=141.147\ km[/tex]
Displacement of the car is 141.147 km
