Answer:
[tex]T=4985.5^{\circ}K[/tex]
Explanation:
The equation that relates heat Q with the temperature change [tex]T-T_0[/tex] of a substance of mass m and specific heat c is [tex]Q=mc(T-T_0)[/tex].
We want to calculate the final temperature T, so we have:
[tex]T=\frac{Q}{mc}+T_0[/tex]
Which for our values means (in this case we do not need to convert the mass to Kg since c is given in g also and they cancel out, but we add [tex]273^{\circ}[/tex] to our temperature in [tex]^{\circ}C[/tex] to have it in [tex]^{\circ}K[/tex] as it must be):
[tex]T=\frac{Q}{mc}+T_0=\frac{40.5J}{(15g)(0.128J/g^{\circ}C)}+(298^{\circ}K)=4985.5^{\circ}K[/tex]
