Respuesta :

Let's solve!

What is [tex]3^{-2}[/tex] ?  [tex]3^{-2}=[/tex] 0.11111111... [continued]

[tex](\frac{1}{3})^{2}=[/tex] 0.11111111... [continued]

[tex](\frac{1}{3})^{-2} = 9[/tex]

[tex]3^{-2}[/tex] · [tex]3^{1}[/tex] = 0.33333333... [continued]

[tex]3^{1} - 3^{-3}=[/tex] 2.962962962... [continued]

Your answer is:

A) [tex](\frac{1}{3})^{2} = 0.11111111...[/tex]

I hope this helps!

PLEASE MARK BRAINLIEST!

gmany

Answer:

[tex]\large\boxed{\left(\dfrac{1}{3}\right)^2}[/tex]

Step-by-step explanation:

[tex]\text{Use}\ a^{-n}=\left(\dfrac{1}{a}\right)^n\\\\3^{-2}=\left(\dfrac{1}{3}\right)^2[/tex]

[tex]\text{Other}\\\\\left(\dfrac{1}{3}\right)^{-2}=\left(\dfrac{3}{1}\right)^2=3^2\\\\3^{-2}\cdot3^1=3^{-2+1}=3^{-1}\\\\3^1-3^{-3}=3-\left(\dfrac{1}{3}\right)^3[/tex]

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