Answer:13.69 KN
Explanation:
Given
mass of bullet [tex]m=0.05 kg[/tex]
Final Speed before leaving Barrel[tex]=575 m/s[/tex]
initial speed[tex](u)=0 m/s[/tex]
time [tex]t=2.1 \times 10^{-3} s[/tex]
we know change in momentum is equal to Impulse imparted
[tex]Fdt=\Delta P[/tex]
where [tex]F=force [/tex]
[tex]\Delta P=change\ in\ Momentum[/tex]
[tex]dt=total\ time[/tex]
[tex]F_{avg}\times 2.1\times 10^{-3}=0.05\cdot (575-0)[/tex]
[tex]F_{avg}=13.69\times 10^{3} N[/tex]
[tex]F_{avg}=13.69 KN[/tex]
