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When the following reaction reached equilibrium at 325 K , the equilibrium constant was found to be 172. When a sample was taken of the equilibrium concentration, it was found contain 0.2 M NO2. What was the equilibrium concentration of N2O4? 2NO2(g) <--> N2O4(g)

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akujorclinton

Answer: 6.88M

Explanation:

K= [N204]/[NO2]^2

[NO2]= 0.2M

K=172

[N204]=K * [N02]^2

172 *0.2^2

=6.88M

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