Answer:
y = [tex]\frac{ - 3}{4}[/tex] x + 5
Step-by-step explanation:
The Line equation is:
y = [tex]\frac{- 3}{4} x - 5[/tex]
The line equation is in the form of y = m x + c
Slop of this line is (m1) = [tex]\frac{ - 3}{4}[/tex]
Let another line with slop (m2) , passes through point (4 , 2)
As per question the another line is parallel to the given line equation
So, slop of both the lines are equal
∴ (m2) = (m1) = [tex]\frac{ - 3}{4}[/tex]
Hence equation of another line with slop [tex]\frac{ - 3}{4}[/tex] and passing through points ( 4 , 2) is
y - y1 = (m2) (y - x1)
I.e y - 2 = [tex]\frac{ - 3}{4}[/tex] (x - 4)
Or, [tex]4\times (y -2) = (- 3)\times (x - 4)[/tex]
Or , 4y - 8 = -3x + 12
Or, 4y = -3x + 12 + 8
Or , 4y = -3x + 20
∴ y = [tex]\frac{ - 3}{4}[/tex] x + 5
Hence The value of y = [tex]\frac{ - 3}{4}[/tex] x + 5 Answer