Answer:
The equation of a line that runs through (-6,2) and is parallel to a line with a slope of (-1/4) is x + 4y - 2 = 0
Step-by-step explanation:
Slope of the parallel equation is m 1 = (-1/4)
If the two liner are parallel the, slope of both lines are equal.
⇒The slope of the equation of line = m2 = m1 = -(1/4)
The point (x0, y0) = (-6,2)
Now, by THE POINT SLOPE FORMULA: The equation of a line is given as
( y - y0) = m (x -x0)
Now, here the equation of line is given as:
[tex]y - 2 = (\frac{-1}{4}) (x - (-6)) \implies 4(y-2) = -1(x + 6)[/tex]
or, 4y - 8 + x + 6 = 0
or, x + 4y - 2 = 0
Hence, the required line equation is x + 4y - 2 = 0
