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Sickle-cell anemia is an inherited chronic blood disease caused by an autosomal recessive allele. Suppose a man who is homozygous recessive for the sickle-cell gene fathers a child by a woman who is a carrier for sickle-cell. What are the chances their children will exhibit the disease? (Note: A Punnett square may be useful.)

Respuesta :

Answer:

50%

Explanation:

Let's suppose that the allele "s" causes sickle cell anemia in homozygous condition. The genotype of the affected male=ss; the genotype of carrier female= Ss. The male will produce all the sperms carrying "s" allele while the female would produce gametes with either "S" or "s" in equal proportion.

A cross between affected male (ss) and carrier female (Ss) would give progeny in the following phenotype ratio= 1/2 normal child: 1/2 affected child. Therefore, there are 50% chances of their child to be affected by the disease.

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