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Dr. Patton is a professor of English. Recently she counted the number of misspelled words in a group of student essays. She noted the distribution of misspelled words per essay followed the normal distribution with a population standard deviation of 2.44 words per essay. For her 10 A.M. section of 40 students, the mean number of misspelled words was 6.05. Construct a 95% confidence interval for the mean number of misspelled words in the population of student essays. (Round your answers to 3 decimal places.)

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Answer:

(5.294 , 6.806) Answer

Explanation:

SD = 2.44

Mean = 6.05

z for 95% confidence interval = 1.96

n=40

Confidence Interval :

( Mean - (z*SD)/sqrt(n) , Mean + (z*SD)/sqrt(n) )

= (6.05 - (1.96*2.44)/sqrt(40) , 6.05 + (1.96*2.44)/sqrt(40) ))

=(5.294 , 6.806) Answer

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