The parallel sides of a trapezium are in the ratio 3:5 and the height between the parallel sides is 10cm.If the bigger of the parallel sides is 30cm, find the area of the trapezium.

Respuesta :

Answer:

[tex]A=240\ cm^2[/tex]

Step-by-step explanation:

Let

x -----> one parallel side of the trapezium

y ----> the other parallel side of the trapezium (bigger side)

we know that

The area of the trapezium is equal to

[tex]A=\frac{1}{2}(x+y)h[/tex] ----> equation A

[tex]\frac{x}{y}=\frac{3}{5}[/tex] ----> [tex]x=\frac{3}{5}y[/tex] ---> equation B

we have

[tex]h=10\ cm\\y=30\ cm[/tex]

Find the value of x

substitute the value of y in the equation B

[tex]x=\frac{3}{5}(30)=18\ cm[/tex]

Find the area

substitute the values in the formula

[tex]A=\frac{1}{2}(18+30)10[/tex]

[tex]A=240\ cm^2[/tex]