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The expanding gases that leave the muzzle of a rifle also contribute to the recoil. A .30 caliber bullet has mass 7.20×10−3 kg and a speed of 601 m/s relative to the muzzle when fired from a rifle that has mass 3.10 kg . The loosely held rifle recoils at a speed of 1.85 m/s relative to the earth. Find the momentum of the propellant gases in a coordinate system attached to the earth as they leave the muzzle of the rifle.

Respuesta :

Answer:

Momentum of propellant will be 1.422 kgm/sec

Explanation:

We have given the mass of bullet [tex]m_{bullet}=7.20\times 10^{-3}kg[/tex]

Velocity of bullet = 601 m /sec

Velocity of rifle with respect to earth = 1.85 m/sec

So velocity of bullet with respect to earth = 601 - 1.85 = 599.15 m/sec

Mass of rifle [tex]m_{rifle}=3.10kg[/tex]

So momentum of rifle [tex]P_{rifle}=3.10\times 1.85=5.735kgm/sec[/tex]

And momentum of bullet [tex]P_{bullet}=7.2\times 10^{-3}\times 599.15=4.313kgm/sec[/tex]

So the momentum of propellant = momentum of rifle - momentum of bullet = 5.735 -4.313 = 1.422 kgm/sec  

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