destinycloyd2005
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For question 1, find the x- and y-intercept of the line.
1. -10x+5y = 40 (1 point)
x-intercept is 5; y-intercept is -10.
x-intercept is 8; y-intercept is -4.
x-intercept is -10;y-intercept is 5.
x-intercept is -4;y-intercept is 8.
For question 2, find the x- and y-intercept of the line.
2. 5x + 4y= 80 (1 point)
x-intercept is 4; y-intercept is 5.
x-intercept is 20; y-intercept is 16.
x-intercept is 5; y-intercept is 4.
x-intercept is 16; y-intercept is 20.
Write y=-x+4 in standard form using integers.
(1 point)
-x-by= 24
-x+6y= 24
Ox+6y=4
6x-y= 24
4. The grocery store sells kumquats for $4.75 a pound and Asian pears for $2.25 a pound. Write an equation (1 point)
in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $22.
4.75k +2.25p = 22
4.75k = 2.25p +22
4.75 +2.25=k
4.75p +2.25k = 22
5. Graph the equation. (1 point)​

2For question 1 find the x and yintercept of the line1 10x5y 40 1 pointxintercept is 5 yintercept is 10xintercept is 8 yintercept is 4xintercept is 10yintercept class=

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Answer:

Part 1) x-intercept is -4;y-intercept is 8

Part 2) x-intercept is 16; y-intercept is 20

Part 3) [tex]x+6y=24[/tex]

Part 4)

Part a) [tex]4.75k+2.25p=22[/tex]

Part b) The graph in the attached figure

Step-by-step explanation:

Part 1) Find the x- and y-intercept of the line

we have

[tex]-10x+5y = 40[/tex]

we know that

The x-intercept is the value of x when the value of y is equal to zero

so

For y=0

[tex]-10x+5(0) = 40[/tex]

[tex]-10x=40[/tex]

[tex]x=-4[/tex]

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

[tex]-10(0)+5y = 40[/tex]

[tex]5y = 40[/tex]

[tex]y=8[/tex]

therefore

x-intercept is -4;y-intercept is 8

Part 2) Find the x- and y-intercept of the line

we have

[tex]5x+4y=80[/tex]

we know that

The x-intercept is the value of x when the value of y is equal to zero

so

For y=0

[tex]5x+4(0)=80[/tex]

[tex]5x=80[/tex]

[tex]x=16[/tex]

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

[tex]5(0)+4y=80[/tex]            

[tex]4y=80[/tex]

[tex]y=20[/tex]              

therefore

x-intercept is 16; y-intercept is 20

Part 3) Write y=-(1/6)x+4 in standard form using integers.

we know that

The equation of a line in standard form is equal to

[tex]Ax+By=C[/tex]

where

A is a positive integer

B and C are integers

we have

[tex]y=-\frac{1}{6}x+4[/tex]

Multiply both sides by 6 to remove the fraction

[tex]6y=-x+24[/tex]

Adds x both sides

[tex]x+6y=24[/tex]

Part 4) The grocery store sells kumquats for $4.75 a pound and Asian pears for $2.25 a pound.

Part a) Write an equation in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $22

Part b) Graph the equation

Part a)

Let

k -----> the number of pounds of kumquats bought

p ----> the number of pounds of Asian pears bough

we know that

The number of pounds of kumquats bought (k) multiplied by it cost of $4.75 a pound plus the number of pounds of Asian pears bough (p) multiplied by it cost of $2.25 a pound must be equal to $22

so

[tex]4.75k+2.25p=22[/tex]

Part b) Graph the equation

To graph the line find out the intercepts

Let

k the first coordinate of the point

p the second coordinate of the point

The k-intercept is the value of k when the value of p is equal to zero

so

For p=0

[tex]4.75k+2.25(0)=22[/tex]

[tex]4.75k=22[/tex]

[tex]k=4.63[/tex]

so

The k-intercept is the point (4.63,0)

The p-intercept is the value of p when the value of k is equal to zero

so

For k=0

[tex]4.75(0)+2.25p=22[/tex]

[tex]2.25p=22[/tex]

[tex]p=9.78[/tex]

so

The k-intercept is the point (0,9.78)

using a graphing tool

Plot the intercepts and join the points to graph the line

see the attached figure

Remember that the weight cannot be a negative number

Ver imagen calculista

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