Answer:
[tex]3x+y=24[/tex]
Step-by-step explanation:
Let the loaves sold be [tex]x[/tex] and rolls sold be [tex]y[/tex].
Given:
Cost for 1 loaf of bread = $3
∴ Cost of [tex]x[/tex] loaves of bread = [tex]3x[/tex]
Cost of 1 roll of bread = $1
∴ Cost of [tex]y[/tex] rolls = [tex]1y[/tex]
Total cost of the baked goods = $24
Therefore, as per question,
[tex]3x+1y=24\\3x+y=24[/tex]
Now, the graph is shown below.
The vertical axis represent the rolls sold and the horizontal axis represent the loaves sold.
Draw a horizontal line from 12 mark on the vertical axis to the given line to meet at point A. Now, from point A, draw a vertical line to meet the horizontal axis at point B. Point B is the number of loaves sold.
From the graph, loaves sold are 4 when rolls sold are 12.
Explanation:
Cost of 1 loaf of bread = $3
Cost of 1 roll = $1
The baker needs to sell both items and it should be worth $24.
To find the linear equation, Suppose, the baker sells “b” loaves of bread and “r” rolls.
Then the total cost of the sales has to be $24.
So, the linear equation will be:
3b + 1r = 24.......................(A)
Now, it is given that the baker sold 12 rolls and we need to know how many loaves he has to sell.
For that, replace the “r” in equation (A) with 12 as “r” represents number of rolls sold.
Then the new equation becomes:
3b + 1 × 12 = 24
or 3b = 24 − 12
or 3b = 12
Solving for “b”,
b = 12/3 = 4 loaves
