Flying against the wind, an airplane travels 3060 kilometers in 3 hours. Flying with the wind, the same plane travels 7560 kilometers in 6 hours. What is the rate of the plane in still air and what is the rate of the wind ?

Answer:
The speed of plane against wind S 1 = 1020 kmph And
The speed of plane with wind S 2 = 1260 kmph
Step-by-step explanation:
Given as :
The distance of airplane against the wind = D 1 = 3060 km
The time taken in against the wind = T 1 = 3 hours
The distance of airplane with the wind = D 2 = 7560 km
The time taken in with the wind = T 2 = 6 hours
Now, Speed of plane against the wind = [tex]\frac{Distance}{Time}[/tex]
So, S 1 = [tex]\frac{D 1}{T 1}[/tex]
Or, S 1 = [tex]\frac{3060}{3}[/tex] = 1020 kmph
Similarly
Speed of plane with the wind = [tex]\frac{Distance}{Time}[/tex]
Or, S 2 = [tex]\frac{D 2}{T 2}[/tex]
Or, S 2 = [tex]\frac{7560}{6}[/tex] = 1260 kmph
Hence The speed of plane against wind S 1 = 1020 kmph And
The speed of plane with wind S 2 = 1260 kmph Answer