Umm how do I solve this

You can also estimate the value of function A: 1 is a little more than halfway between -5 and 5, so the y-value of function A will be a little more than halfway between -9 and +11, perhaps near 2.

Evaluating function B at x=1 tells you its value is 10 at x=1, so way more than the value of function A.

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If you bother to figure out the slope and y-intercept of function A, you find it obeys the equation ...

y = 2x +1

Evaluated at x=1, function A gives y = 3, so is less than 10.

The y-value of Function A when x=1 is less than the y-value of Function B when x=1.

wolfpackgirl228 wolfpackgirl228 · Answer 2 · 2019-11-09T23:19:22+01:00

Answer:

The y-value of function A when x=1 is less than the y-value of function B when x=1.

Step-by-step explanation:

The equation for function b is known, so in order to compare, the equation for function A has to be found.

That can be done by putting two ordered pairs into slope formula.

y2-y1/x2-x1

11+13/5+7=24/12=2

So, the slope is 2.

Then, using one ordered pair and the slope, it can be put into point-slope form.

y-y1=m(x-x1)

y-11=2(x-5)

From there, it can be put into slope-intercept form so it can be compared.

y-11=2x-10

+11 +11

y=2x+1

compared to

y=5x+5

For y=2x+1, when x=1, y=3

For y=5x+5, when x=1, y=10

Therefore, the y-value of function A when x=1 is less than the y-value of function B when x=1.