Answer:m=5.25 kg
Explanation:
Given
Initial angular momentum [tex]I_1=46 kg-m^2[/tex]
[tex]N_1=44 rpm[/tex]
[tex]\omega _1=\frac{2\pi N_1}{60}=4.60 rad/s[/tex]
Potter drop a lump of clay such that speed decreases to 35 rpm
[tex]N_2=35 rpm [/tex]
[tex]\omega _2=\frac{2\pi \cdot 35}{60}=3.66 rad/s[/tex]
Moment of inertia after dropping lump of let say mass m
[tex]I_2=46+m\times 1.5^2[/tex]
[tex]I_1\omega _1=I_2\omega _2[/tex]
[tex]46\times 4.6=I_2\times 3.66[/tex]
[tex]I_2=57.81 kg-m^2[/tex]
[tex]46+m\times 1.5^2=57.81[/tex]
[tex]m=5.25 kg[/tex]
