Answer:
Explanation:
FIrst let c be the specific heat, now we need the heat that the device is able to provide:
so it is turned on for 5 minutes (300 seconds) with 25 Watts
[tex]Q = Power*time = (25)*(300) = 7500J[/tex]
Now heat is equal to the change in internal energy, where we will use the remaining terms.
Now we continue
[tex]Q = \Delta U = M*C(\Delta T)[/tex]
where [tex]\Delta T[/tex] is the change of temperature ( [tex]\Delta T = T_{final} - T_{initial}[/tex] )
now [tex]Q = \Delta U = M*C*(T_{final} - T_{initial})[/tex]
We solve [tex] T_{final} = \frac{Q}{M*C} +T_{initial} [/tex]
now we just plot it for different values of M using any software..
please find attached the plot of the temperature.
The result indicates that as the mass increases it is harder for the system to reach higher final temperatures.
