Answer:
[tex]y=\frac{1}{3}x[/tex]
[tex]y=\frac{1}{6}x+10[/tex]
Step-by-step explanation:
Let x be the number of throws and y be the cost
Without armband case
The cost for 3 throws is $1
The cost for 1 throws is [tex]\frac{1}{3}[/tex]
The cost for x throws is [tex]\frac{1}{3}x[/tex]
So,[tex]y=\frac{1}{3}x[/tex] is the equation for the game in terms of the number of throws purchased without an armband
With armband case
The cost for 6 throws is $1
The cost for 1 throws is [tex]\frac{1}{6}[/tex]
The cost for x throws is [tex]\frac{1}{6}x[/tex]
Cost of Arm band is $10
So, Total cost for x throws with arm band = [tex]\frac{1}{6}x+10[/tex]
So, [tex]y=\frac{1}{6}x+10[/tex]is the equation for the game in terms of the number of throws purchased with an armband