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Balance the following equation. Then determine the mole ratio of Ca(OH)2:Al(OH)3. Al2(SO4)3 + Ca(OH)2 Al(OH)3 + CaSO4

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To balance the reaction, we look at the number of atoms of each element we have. It should be equal for both sides. The balanced reaction is:

Al2(SO4)3 + 3Ca(OH)2 =  2Al(OH)3 + 3CaSO4

The ratio of calcium hydroxide and aluminum hydroxide is 3:2.

Answer: The mole ratio of [tex]Ca(OH)_2:Al(OH)_3[/tex] is 3 : 2

Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed, but it can only be transformed from one form to another. In a chemical reaction, total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.

All the balanced chemical equation follows law of conservation of mass.

The balanced chemical equation for the combination of aluminium sulfate with calcium hydroxide is:

[tex]Al_2(SO_4)_3+3Ca(OH)_2\rightarrow 2Al(OH)_3+3CaSO_4[/tex]

Mole ratio of any two compounds is basically the ratio of their stoichiometric coefficients.

Hence, the mole ratio of [tex]Ca(OH)_2:Al(OH)_3[/tex] is 3 : 2

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