Adam, Beth, and Carly walked a total of 10 miles collectively. Beth walked twice as far as Adam, and she walked a half a mile further than Carly. If a = number of miles Adam walks, b = number of miles Beth walks, and c = number of miles Carly walks, which equation is NOT true for this situation?
A) b = 2a
B) b = c + 0.5
C) 3a + c = 10
D) a + 2c = 10.5

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Ckaranja Ckaranja · Answer 1 · 2016-06-15T03:46:10+02:00

D) a+2c=10.5

Since b=c+[tex] \frac{1}{2} [/tex]
a+b+c=10
a+(c+1/2)+c=10
a+2c+1/2=10
a+2c=9.5

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RenatoMattice RenatoMattice · Answer 2 · 2018-10-17T07:04:33+02:00

Answer: Option 'D' is not correct.

Step-by-step explanation:

Since we have given that

Total distance walked by Adam , Beth, and Carly = 10 miles

Let number of miles Adam walks be a

Let number of miles Beth walks be b

Let number of miles Carly walks be c

According to question,

Beth walked twice as far as Adam

So, the equation will be

[tex]b=2a[/tex]

Thus, Option 'A' is satisfied.

Now, Beth walked a half a mile further than Carly.

So, the equation will be

[tex]b=c+0.5[/tex]

Thus, Option 'B' is correct.

Now, we substitute the first equation, then we get

[tex]a+b+c=10\\a+2a+c=10\\3a+c=10[/tex]

Thus, Option 'C' is correct.

The only incorrect equation is Option 'D' .