Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0×1012 electrons are added to sphere A, then the two spheres are separated. Afterward, what are the charge of A and the charge of B?

Respuesta :

Answer:

[tex]Q_A=80 nC[/tex],[tex]Q_B=80 nC[/tex],

Explanation:

Knowing both spheres are identical means after the equilibrium both will have equal charge so added [tex]1.0x10^{12} e[/tex]

So to determine the charge of both spheres can use

[tex]Q_A=Q_B[/tex]

[tex]Q=1.6x10^{-19}C[/tex]

[tex]Q_A=Q_B=Q_{total}[/tex]

[tex]Q_{total}= - 1.0x10^{12}C * - 1.6x10^{-19}C[/tex]

[tex]Q_{total}=1.6x10^{-7}C[/tex]

Both spheres are identical so

[tex]Q_A=Q_B=\frac{Q_{total}}{2}[/tex]

[tex]Q_A=Q_B=\frac{1.6x10^{-7}}{2}=80x10^{-9}C[/tex]