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Sulfur tetrafluoride SF4, reacts slowly with oxygen,O2, to form sulfur tetrafluoride monoxideOSF4, according to the following unbalancedreaction:
SF4(g)+O2(g) → OSF4(g)
When the equation is balanced what are thecoefficients?

Respuesta :

anfabba15

Answer:

2SF₄ (g)  +   O₂ (g)  →   2OSF₄(g)

2 moles of sulfur tetrafluoride reacts with 1 mol of oxygen to make 2 moles of tetrafluoride monoxide

Explanation:

2SF₄ (g)  +   O₂ (g)  →   2OSF₄(g)

As we have two oxygens in reactants, we add 2 moles of OSF₄. That made us to put a 2 in SF₄ to ballance it, so we finally get 2 S, 8 F and 2 O in reactants and the same numbers in products.

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