Answer: 1/9
Step-by-step explanation:
the total number of combinations or outcomes when 2 dice are rolled is 36 ( count all or simply the formula for total number of combinations or outcomes when n dice are rolled is [tex]6^{n}[/tex] )
sum possibilities probability(favorable/ total outcomes of the event)
2 (1,1) 1/36
3 (1,2) , (2,1) 2/36
4 (2,2), (3,1) , (1,3) 3/36
5 (4,1), (1,4),(2,3),(3,2) 4/36
6 (1,5),(5,1),(2,4),(4,2),(3,3) 5/36
7 (2,5),(5,2)(1,6),(6,1),(3,4),(4,3) 6/36
8 (2,6),(6,2), (5,3),(3,5),(4,4) 5/36
9 (3,6),(6,3),(5,4),(4,5) 4/36
10 (5,5),(4,6),(6,4) 3/36
11 (6,5),(5,6) 2/36
12 (6,6) 1/36
probability that the sum will be less than 3 or greater than 10 = probability for sum to be 2 + probability for sum to be 11 + probability for sum to be 12
= 1/36 + 2/36 + 1/36
= 4/36
= 1/9