Answer:
409.67 °C
Explanation:
At constant pressure and temperature, using Charle's law as:-
[tex]\frac {V_1}{T_1}=\frac {V_2}{T_2}[/tex]
Given ,
V₁ = 604 mL
V₂ = 838 mL
T₁ = 219 °C
T₂ = ?
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (219 + 273.15) K = 492.15 K
Using above equation as:
[tex]\frac{604\ mL}{492.15\ K}=\frac{838\ mL}{T_2}[/tex]
[tex]T_2=\frac{838\times 492.15}{604}\ K=682.82\ K[/tex]
In Celsius, the temperature is:- 682.82-273.15 °C = 409.67 °C
